sin (A+B)=sin A cos B + cos A sin B ___> (1)
sin (A-B)=sin A cos B - cos A sin B ___> (2)
sin (A-B)=sin A cos B - cos A sin B ___> (2)
cos (A+B)=cos A cos B - sin A sin B ___> (3)
cos (A-B)=cos A cos B + sin A sin B ___> (4)
(1)+(2)
(1)-(2)
2 cos A sin B = sin (A+B)-sin (A-B)
(3)+(4)
2 cos A cos B = cos (A+B) + cos (A-B)
(3)-(4)
(-)2 sin A cos B = cos (A+B)- cos (A-B)
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sin(A+B)+sin(A-B)= 2 sin A cos B___> (5)
sin(A+B)-sin(A-B)= 2 cos A sin B___> (6)
cos(A+B)+cos(A-B)= 2 cos A cos B___> (7)
cos(A+B)-cos(A-B)=(-)2sin A sin B ___> (8)
A+B = C ___> (@)
A-B = D ___> (@@)
(@@)හා (@)මගින්
A=[C+D]/2
B=[C-D]/2
හා (5),(6),(7),(8) මගින්
එම නිසා
sin C + sin D = 2sin([C+D]/2)cos([C-D]/2)
sin C - sin D = 2cos([C+D]/2)sin([C-D]/2)
cos C + cos D = 2cos([C+D]/2)cos([C-D]/2)
cos C + cos D =(-)2sin([C+D]/2)sin([C-D]/2)
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sin(A+B)+sin(A-B)= 2 sin A cos B___> (5)
sin(A+B)-sin(A-B)= 2 cos A sin B___> (6)
cos(A+B)+cos(A-B)= 2 cos A cos B___> (7)
cos(A+B)-cos(A-B)=(-)2sin A sin B ___> (8)
A+B = C ___> (@)
A-B = D ___> (@@)
(@@)හා (@)මගින්
A=[C+D]/2
B=[C-D]/2
හා (5),(6),(7),(8) මගින්
එම නිසා
sin C + sin D = 2sin([C+D]/2)cos([C-D]/2)
sin C - sin D = 2cos([C+D]/2)sin([C-D]/2)
cos C + cos D = 2cos([C+D]/2)cos([C-D]/2)
cos C + cos D =(-)2sin([C+D]/2)sin([C-D]/2)
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